Răspuns:
a) -2(x-3)+3(2-x)=x
-2x+6+6-3x=x
5x-x= -12
-6x=-12x
x=2
c) 3x-5(x+ v2)=v2-4r
3x-5x-5v2=v2-4r
-2x-5v2=v2-4r
-2x=v2-4r+5v2
-2x=6v2-4r
x=3v2+2r
X=-3v2+2r, rER
e) 6(x+3)+3(x-2)=10
6x+18+3x-6=10
9x+12=10
9x=10-12
9x=-2
g)2(5x+1)-(2x-1)+9x=6
10× +2-2x +1+9x=6
17x+3=6
17x=6-3
17x=3