Răspuns :

Zzandru016id

Răspuns:

5+[32-(10:a•4+12)]•7=89

[32-(10:a•4+12)]•7=89-5

[32-(10:a•4+12)]•7=84

32-(10:a•4+12)=84÷7

32-(10:a•4+12)=12

10÷a×4+12=32-12

10÷a×4+12=20

10÷a×4=20-12

10:a×4=8

10:a=8:4

10:a=2

a=10:2

a=5

Petronel5froneaid

SALUT!

5+[32-(10:a•4+12•7)]•7=89

Metoda mersului invers

[32-(10:a•4+12)=84

32-(10:a•4+12)=12

10:a•4+12=44

a•4+12=440

a•4=428

a=428:4

a=17

Sper să te fi ajutat ;)

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