Răspuns :

Miky93id
a-b=50
a:b=3 rest 10
a=3b+10

3b+10-b=50
2b=50-10
2b=40
b=20
a=60+10=70
Nicolamgdid
a-b=50
a:b=3 r. 10
 Teorema impartirii cu rest:  a=3b+10
inlocuim in diferenta: 3b+10-b=50=>2b+10=50|-10=> 2b=40|:2=>b=20
a=(3x20+10)-20=70-20=50

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