Răspuns:
niu=5molSO3
1mol...........................1mol
SO3 + H2O---> H2SO4
5mol..................................x
x= 5mol H2SO4
miu,H2SO4=98g/mol
m,=niuxmiu= 5x98g=490g=md
c= mdx100/ms, unde ms= md+m,apa= 490g+510g=1000g
c=490x100/1000= 49%
Explicație: