a fost răspuns

a) (-1–2–3–... -99)+(2+3+4+...+100);
b) (2+4+6+...+100)+(-1-3-5-... -99);
c) (-3-6-9-..-99)+(4+7+10+...+100);
d) (4+8+12+...+100)+(-6-10–14 ....-102);
e) (-5-10-15-...-100)+(100+95+90+...+5).​

Răspuns :

102533id

Răspuns:

Explicație pas cu pas:

a) (-1–2–3–... -99)+(2+3+4+...+100) =

= (2-1)+(3-2)+(4-3)+.....(100-99) = 1+1+1+....+1 de 99 ori 1 = 99

b) (2+4+6+...+100)+(-1-3-5-... -99) = (2-1)+(4-3)+(6-5)+...+(100-99) =

= 1+1+1+...+1 [de (100-2):2+1 ]= 50 de ori 1 = 50

c) (-3-6-9-..-99)+(4+7+10+...+100) = (4-3)+(7-6)+.....+(100-99) =

= 1+1+1+...+1 de [ (100-4):3+1 = 33 de ori 1 = 33

d) (4+8+12+...+100)+(-6-10–14 ....-102) = (4-6)+(8-10)+....+(100-102) =

= (-2)+(-2)+...+(-2) de [(100-4):4+1 = 25 de ori -2 = -50

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