[tex] \color{red}\LARGE \boxed{ \bf a = 60}[/tex]
Explicație pas cu pas:
Bună!
[tex] \large \bf \dfrac{1}{5} \cdot a + 3 = \dfrac{1}{4} \cdot a [/tex]
[tex] \large \bf \dfrac{a}{5} + 3 = \dfrac{a}{4} \: \: \: \: \bigg | \cdot5[/tex]
[tex]\large \bf a+ 15 = \dfrac{5a}{4} \: \: \: \: \bigg | \cdot4[/tex]
[tex]\large \bf 4a + 60 = 5a[/tex]
[tex]\large \bf 60 = 5a - 4a[/tex]
[tex] \color{blue}\Large \boxed{ \bf a = 60}[/tex]
==pav38==
