Răspuns:
Explicație:
1.
Al2 O3 CuSO4
Na2 O H2SO4
CaO H2 CO3
SO3 Na2CO3
P2O5 Ca3(PO4)2
Al(OH)3 Cl ; Cl2
2.
MAl2O3= 2.27 + 3.16=102-------> 102 g/moli
MNa2O= 2.23 + 16= 62------> 62g/moli
MCaO =40 +16=56------> 56g/moli
MSO3= 32 + 3.16=80-----> 80g/moli
MP2O5= 2.31 + 5.16=142------>142g/moli
MAl(OH)3 = 27 + 3.16 +3 =78-------> 78g/moli
MCuSO4= 64 + 32 + 4.16=160 ------> 160g/moli
MH2SO4= 2 + 32 + 4.16=98-------> 98g/moli
MH2CO3= 2 + 12 + 3.16=62-----> 62g/moli
MNa2CO3= 2.23 + 12 + 3.16=106-----> 106 g/moli
M Ca3(PO4)2= 3.40 + 2.31 + 8.16=310-------> 310 g/moli
MCl2= 2.35,5= 71 ------> 71g/moli
3. H2CO3
r.m = 2AH : AC : 3AO
= 2 : 12 : 48
= 1 : 6 : 24
1+ 6 + 24=31
31g H2CO3 --------1g H ----------6g C----------24g O
100g ----------------------x----------------y--------------z
x= 100. 1 : 31=3,23% H
y= 100.6 : 31=19,35% C
z= 100.24 : 31=77,42% O
MH2CO3= 2 +12 +3.16= 62------> 62g/moli
62g H2CO3---------2g H-------12g C--------48g
100g ------------------x----------------y-------------z
x= 100.2 : 62=3,23% H
y=
z=
calculeaza ! este la fel ca mai sus
4.
m= n . M
m= 4moli .310g/moli= 1240 g Ca3(PO4)2
