Răspuns:
1.
H3C –CH2- CH3+ Cl2→H3C-CH2- CH2-Cl+ HCl
2.
C4H10
MC4H10=4×12+1×10=58g/mol
58gC4H10...............................48gC.............................10gH
100gC4H10..............................xgC..............................ygH
x=100×48/58=calculeaza
y=100×10/58=calculeaza
Explicație:
