Răspuns:
Explicație pas cu pas:
[tex]\large \bf 2,3\cdot2,3\cdot2,3 = \bigg(2,3\bigg)^{3} =\bigg(\dfrac{23}{10} \bigg)^{3}[/tex]
[tex]\it~~[/tex]
[tex]\large \bf 0,4\cdot0,4\cdot0,4 = \bigg(0,4\bigg)^{3} =\bigg(\dfrac{4}{10} \bigg)^{3}= \bigg(\dfrac{2}{5} \bigg)^{3}[/tex]
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