Răspuns:
Explicație pas cu pas:
a) (2/3)⁵·(2/3)⁷ = (2/3)⁵⁺⁷ = (2/3)¹²
b) (3/10)³·(3/10)¹⁰ = (3/10)³⁺¹⁰ = (3/10)¹³
c) (11/5)⁴·(11/5)⁶ = (11/5)⁴⁺⁶ = (11/5)¹⁰
d) (3/4)¹¹:(3/4)⁴ = (3/4)¹¹⁻⁴ = (3/4)⁷
e) (8/3)⁹:(8/3)⁸ = (8/3)⁹⁻⁸ = 8/3
f) (13/17)²²:(13/17)²⁰ = (13/17)²²⁻²⁰ = (13/17)² = 169/289
g) [(2/5)⁵]¹¹ = (2/5)⁵ˣ¹¹ = (2/5)⁵⁵
h) [(14/27)⁶]⁴ = (14/27)⁶ˣ⁴ = (14/27)²⁴
i) [(3/100)⁰]²⁰¹⁹= (3/100)⁰ˣ²⁰¹⁹ = (3/100)⁰ = 1
sau [(3/100)⁰]²⁰¹⁹= 1²⁰¹⁹ = 1
Am folosit formulele :
aⁿ·aᵇ = aⁿ⁺ᵇ
aⁿ:aᵇ = aⁿ⁻ᵇ
(aⁿ)ᵇ = aⁿˣᵇ
a⁰ = 1
1ⁿ = 1
