Răspuns :

Argon08id

Răspuns:

Explicație pas cu pas:

Vezi imaginea Argon08
Targoviste44id

[tex]\it x^2-3x+2=0\\ \\ \Delta = b^2-4ac=3^2-4\cdot1\cdot2 =9-8=1\\ \\ x_{1,2}=\dfrac{-b\pm\sqrt{\Delta}}{2a}=\dfrac{3\pm\sqrt1}{2}=\dfrac{3\pm1}{2}\\ \\ \\ x_1=\dfrac{3-1}{2}=\dfrac{2}{2}=1\\ \\ \\ x_2=\dfrac{3+1}{2}=\dfrac{4}{2}=2[/tex]

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