Răspuns :
PV = nRT ; n = m/M
PVM = mRT
P= 5 atm, m= 528 g M.CO2 = 12+2x16 = 44 g/mol
T= 273+227 = 500 K
=> V = mRT/PM
= 528x0,082x500/5x44 = 98,4 L
PV = [tex]\pi[/tex]RT
n=m/M
PVM = mRT
P - 5 atm
m = 528 g M CO2 = 12+2×16=12+32=44[tex] \frac{g}{mol} [/tex]
T = 273K+227K=500K
528×0,082 ×500/5 × 44} = 98.4