Răspuns :

c)

[tex] \frac{1}{6} + 1 \frac{1}{2} \times ( \frac{3}{4} - \frac{1}{2} ) \\ = \frac{1}{6} + \frac{3}{2} \times ( \frac{3}{4} - \frac{2}{4} ) \\ = \frac{1}{6} + \frac{3}{2} \times \frac{1}{2} \\ = \frac{1}{6 } + \frac{3}{4} \\ = \frac{2}{12} + \frac{6}{12} \\ = \frac{8}{12} = \frac{2}{3} [/tex]

d)

[tex]1 \frac{2}{15} - \frac{1}{4} \div (2 \frac{1}{3} + \frac{1}{2} \times 1 \frac{1}{3} ) \\ = \frac{17}{15} - \frac{1}{4} \div ( \frac{7}{3} + \frac{1}{2} \times \frac{4}{3} ) \\ = \frac{17}{15} - \frac{1}{4} \div ( \frac{7}{3} + \frac{4}{6} ) \\ = \frac{17}{15} - \frac{1}{4} \div ( \frac{7}{3} + \frac{2}{3} ) \\ = \frac{17}{15} - \frac{1}{4} \div \frac{9}{3} \\ = \frac{17}{15} - \frac{1}{4} \times \frac{3}{9} \\ = \frac{17}{15} - \frac{3}{36} \\ = \frac{204}{108} - \frac{15}{108} \\ = \frac{189}{108} = \frac{63}{60} = \frac{21}{20} [/tex]

sper ca te-am ajutat