Răspuns :

[tex]\it \Big(4\dfrac{1}{6}\Big)^{12}:\Big(11\dfrac{1}{9}\Big)^6=\Big(\dfrac{25}{6}\Big)^{12}:\Big(\dfrac{100}{9}\Big)^6=\Big(\dfrac{25}{6}\Big)^{12}:\Big(\dfrac{10^2}{3^2}\Big)^{6}=\\ \\ \\ =\Big(\dfrac{25}{6}\Big)^{12}:\Big(\dfrac{10}{3}\Big)^{12}=\Big(\dfrac{25}{6}:\dfrac{10}{3}\Big)^{12}=\Big(\dfrac{25}{6}\cdot\dfrac{3}{10}\Big)^{12}=\Big(\dfrac{25\cdot3}{6\cdot10}\Big)^{12}=\\ \\ \\ =\Big(\dfrac{\ 75^{(15}}{60}\Big)^{12}=\Big(\dfrac{5}{4}\Big)^{12}[/tex]