Răspuns:
[tex]\bf c)~~\color{teal}\large\boxed{\bf \dfrac{\sqrt{2}}{108}}[/tex]
[tex]\bf g)~~\color{Teal}\large\boxed{\bf \dfrac{5\sqrt{5}}{8}}[/tex]
Explicație pas cu pas:
Buna!
[tex]\color{CC0000}\Large\boxed{\boxed{\bf \Large Formule:a^{-n}= \dfrac{1}{a^{n}};~~ \bigg(\dfrac{a}{b}\bigg)^{-n}= \bigg(\dfrac{b}{a}\bigg)^{n} }}[/tex]
[tex]\it~~~~[/tex]
[tex]\bf c)~(3\sqrt{2})^{-3}= \dfrac{1}{(3\sqrt{2})^{3}}= \dfrac{1}{27\cdot2\sqrt{2}}=\dfrac{1}{54\sqrt{2}}\cdot \dfrac{\sqrt{2}}{\sqrt{2}}=\dfrac{\sqrt{2}}{54\cdot2}=\boxed{\boxed{\bf \dfrac{\sqrt{2}}{108}}}[/tex]
[tex]\it~~[/tex]
[tex]\bf g)~\bigg(\dfrac{2}{\sqrt{5}}\bigg)^{-3}=\bigg(\dfrac{\sqrt{5}}{2}\bigg)^{3}= \dfrac{(\sqrt{5})^{3} }{{2}^{3}}= \boxed{\boxed{\bf \dfrac{5\sqrt{5}}{8}}}[/tex]
PS: Daca esti pe telefon, te rog sa glisezi spre dreapta pentru a vedea rezolvarea completa
==pav38==
