Răspuns:
Salut!
[tex] \frac{ {2}^{24} }{ {3}^{16} } = \frac{ { {2}^{3} }^{8} }{ { {3}^{2} }^{8} } = \frac{ {6}^{8} }{ {6}^{8} }fractia \: este \: echiunitara[/tex]
b)
[tex] \frac{ {2}^{10} + {2}^{9} }{ {2}^{11} } = \frac{ {2}^{9}(2 + 1) }{ {2}^{11} } = \frac{ {2}^{9} \times 3 }{ {2}^{11} } = \frac{3}{ {2}^{2} } = \frac{3}{4} fractia \: este \: subunitara - 3 < 4[/tex]
c)
[tex] \frac{ {2}^{16} }{ {4}^{9} } = \frac{ {4}^{8} }{ {4}^{9} } = > > {4}^{8} < {4}^{9} - fractie \: subunitara [/tex]
d)
[tex] \frac{ {9}^{10} }{ {27}^{7} } = \frac{ {3}^{20} }{ {3}^{21} } = > > {3}^{20} < {3}^{21} - fractie \: subunitara [/tex]
Sper că te-am ajutat!
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