Răspuns:
-CALCULEZ MASA SI MOLI DE ACID
ms=250g c=15%
c=mdx100/ms---> md= 15x250/100g=37,5g H2SO4
-CALCULEZ, din ecuatia chimica, masa de NaOH care intra in reactie cu acidul,stiind miu,NaOH=40g/mol miuH2SO4=98g/mol
2X40g........98g
2NaOH + H2SO4----> Na2SO4+ 2H2O
x...................37,5g.
x=m=30,6gNaOH
-calculez moli baza
niu=m/miu=30.6/40mol=0,765molNaOH
-calculez CONCENTRATIA SOLUTIEI DE BAZA
c= niu/V=0,765mol/0,020 L=38,25M
Explicație:
