Răspuns:
Explicație pas cu pas:
(3-4x)²-(x-3)² = (3-4x-x+3)(3-4x+x-3) = (6-5x)(-3x) = 3x(5x-6)
(11x-6)²-(3x-1)² = (11x-6-3x+1)(11x-6+3x-1) = (8x-5)(14x-7) = 7(8x-5)(2x-1)
(7-2x)²-(x+2)² = (7-2x-x-2)(7-2x+x+2) = (5-3x)(9-x) = (x-9)(3x-5)
(3x-5)²-(2x-3)² = (3x-5-2x+3)(3x-5+2x-3) = (x-2)(5x-8)
4(6-5x)²-(x²-x+3)² = [2(6-5x)]² - (x²-x+3)² = (12-10x)² - (x²-x+3)² =
= (12-10x-x²+x-3)(12-10x+x²-x+3) = (-x²-9x+9)(x²-11x+15)
Am folost formula :
a²-b² = (a-b)(a+b)
