Răspuns :

=5x-6supra12-3x + 1supra18 = 4x-3supra9-2x + 3supra6 - 5supra36
=5x-6supra12-3x + 1supra18 = 4x-3supra9-2x + 13supra36
=5x-6supra12-3x + 1supra18 - 4x-3supra9-2x - 13supra36 = 0
=5x-6supra3(4-x) - 11supra36 - 4x-3supra9-2x = 0
=12(9-2x)•(5x-6)-11(4-x)•(9-2x)-36(4-x)•(4x-3)supra36(4-x)•(9-2x) = 0
=(108-24x)•(5x-6)+(-44+11x)•(9-2x)+(-144+36x)•(4x-3)supra36(4-x)•(9-2x) = 0
=540x-648-120x la puterea2+144x-396+88x+99x-22x la puterea2-576x+432+144x la puterea 2-108xsupra36(4-x)•(9-2x) = 0
=187x-612+2x la puterea2supra36(4-x)•(9-2x)=0
=187x-612+2x la puterea2=0
=2x la puterea 2+187x-612=0
x=-187+-radical187laputerea2-4•2•(-612)supra2•2
x=-187+-radical34969+4896supra4
x=-187+-radical39865supra4
x=-187+radical39865supra4 x=-187-radical39865supra4
x1=-187+radical39865supra4
x2=-187-radical39865supra4

sper ca te am putut ajuta!!!