Salut!
Distanta AB = [tex]\sqrt{(3-2)^2+(5-(-1))^2} = \sqrt{1^2 + 6^2} = \sqrt{1 + 36} = \sqrt{37}[/tex]
Rezultat: [tex]\sqrt{37}[/tex]
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Formula distantei a doua puncte in reperul cartezian xOy:
- [tex]\sqrt{(x_{2}-x_{1})^2 + (y_{2}- y_{1})^2 }[/tex]
Succes!
