Răspuns: Ai mai jos rezolvarea
Explicație pas cu pas:
Buna!
[tex]\bf a)~~ (2\sqrt{675}-5\sqrt{192} ):(2\sqrt{5^{2} } )=[/tex]
[tex]\bf (2\sqrt{3 \cdot 15^{2}} - 5\sqrt{3 \cdot 8^{2}}) : (2 \cdot 5 )=[/tex]
[tex]\bf (2\cdot 15\sqrt{3}-5\cdot 8\sqrt{3} ):10=[/tex]
[tex]\bf (30\sqrt{3}-40\sqrt{3} ):10=[/tex]
[tex]\bf (-10\sqrt{3}):10=\boxed{\boxed{\bf -\sqrt{3}}}[/tex]
[tex]\it~~[/tex]
[tex]\bf b)~~ (\sqrt{125}-\sqrt{405}):\sqrt{5}- (\sqrt{1134}-\sqrt{504}):\sqrt{7} =[/tex]
[tex]\bf (5\sqrt{5}-9\sqrt{5}):\sqrt{5}- (9\sqrt{14}-6\sqrt{14}):\sqrt{7} =[/tex]
[tex]\bf (-4\sqrt{5}):\sqrt{5}- 3\sqrt{14}:\sqrt{7} =[/tex]
[tex]\bf -4\sqrt{5}:\sqrt{5}- 3\sqrt{2} =[/tex]
[tex]\boxed{\boxed{\bf -4- 3\sqrt{2}}}[/tex]
[tex]\it~~[/tex]
[tex]\bf c)~~ (\sqrt{726}-\sqrt{864}):\sqrt{6}-\sqrt{6}\cdot(\sqrt{216}-\sqrt{600}) =[/tex]
[tex]\bf (11\sqrt{6}-12\sqrt{6}):\sqrt{6}-\sqrt{6}\cdot(6\sqrt{6}-10\sqrt{6}) =[/tex]
[tex]\bf -\sqrt{6}:\sqrt{6}-\sqrt{6}\cdot(-4\sqrt{6}) =[/tex]
[tex]\bf -1 + 4\cdot 6 =[/tex]
[tex]\bf -1+24[/tex]
[tex]\boxed{\boxed{\bf 23}}[/tex]
[tex]\it~~[/tex]
[tex]\bf d)~~\sqrt{5}\cdot (\sqrt{1445}-\sqrt{845})+(\sqrt{1620}-\sqrt{1805}):\sqrt{5} =[/tex]
[tex]\bf \sqrt{5}\cdot (17\sqrt{5}-13\sqrt{5})+(18\sqrt{5}-19\sqrt{5}):\sqrt{5} =[/tex]
[tex]\bf \sqrt{5}\cdot (4\sqrt{5})-\sqrt{5}:\sqrt{5} =[/tex]
[tex]\bf \sqrt{5} \cdot 4\sqrt{5} -\sqrt{5}:\sqrt{5} =[/tex]
[tex]\bf 4 \cdot 5 -1 =[/tex]
[tex]\bf 20 -1 =[/tex]
[tex]\boxed{\boxed{\bf 19}}[/tex]
PS: Daca esti pe telefon te rog sa glisezi spre dreapta pentru a vedea rezolvarea completa.
==pav38==
