Răspuns:
Aducem la acelasi numitor.
a) [tex] \frac{2}{5} + \frac{3}{10} = \frac{2 \times 2}{10 } + \frac{3}{10} = \frac{4 + 3}{10} = \frac{7}{10} [/tex]
b) [tex] \frac{2}{9} + \frac{2}{3} = \frac{2}{9} + \frac{2 \times 3}{9} = \frac{2 + 6}{9} = \frac{8}{9} [/tex]
c) [tex] \frac{3}{4} + \frac{5}{8} = \frac{3 \times 2}{8} + \frac{5}{8} = \frac{6 + 5}{8} = \frac{11}{8} [/tex]
d) [tex] \frac{7}{8} + \frac{1}{2} = \frac{7}{8} + \frac{4 \times 1}{8} = \frac{7 + 4}{8} = \frac{11}{8} [/tex]
e) [tex] \frac{1}{2} + \frac{1}{4} = 1 \times 2 + \frac{4}{4} = \frac{2 + 1}{4} = \frac{3}{4} [/tex]
f) [tex] \frac{3}{10} + \frac{2}{5} = \frac{3}{10} + \frac{2 \times 2}{10} = \frac{3 + 4}{10} = \frac{7}{10} [/tex]
g) [tex] \frac{1}{6} + \frac{2}{3} = \frac{1}{6} + 2 \times 2 = \frac{1 + 4}{6} = \frac{5}{6} [/tex]
h) [tex] \frac{3}{5} + \frac{1}{20} = \frac{3 \times 4}{20} + \frac{1}{20} = \frac{12 + 1}{20} = \frac{13}{20} [/tex]
Sper ca te-am ajutat. - M1hai15
