Răspuns:
[tex]a){(x - 1)}^{2} = 0 = > x - 1 = 0 = > x = 1 \\b)(x + 1)(x - 6) = 0 = > \\ x + 1 = 0 = > x = - 1 \\ x - 6 = 0 = > x = 6 \\ c)3 {x}^{2} - 12 = 0 = > 3( {x}^{2} - 4) = 0 = > 3(x + 2)(x - 2) = 0 \\ x + 2 = 0 = > x = - 2 \\ x - 2 = 0 = > x = 2 \\ d) {6x}^{2} - x = 0 = > x(6x - 1) = 0 \\ x = 0 \\ 6x - 1 = 0 = > 6x = 1 = > x = \frac{1}{6} [/tex]
