Răspuns: 1261
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[tex]\bf 1488-7:[6-5\cdot(32:8-4:n)+ 1]-6 -1288=193[/tex]
[tex]\bf 1488-7:[6-5\cdot(4-4:n)+ 1]-6 -1288=193[/tex]
[tex]\bf 1488-7:[6-5\cdot(4-4:n)+ 1]=193 +6 + 1288[/tex]
[tex]\bf 1488-7:[6-5\cdot(4-4:n)+ 1]=1487[/tex]
[tex]\bf 1488-1487 = 7:[6-5\cdot(4-4:n)+ 1][/tex]
[tex]\bf 1 = 7:[6-5\cdot(4-4:n)+ 1][/tex]
[tex]\bf [6-5\cdot(4-4:n)+ 1] = 7[/tex]
[tex]\bf 6-5\cdot(4-4:n)+ 1 = 7[/tex]
[tex]\bf 7 -5\cdot(4-4:n) = 7[/tex]
[tex]\bf 7= 7 + 5\cdot(4-4:n)[/tex]
[tex]\bf 7= 7 + 20- 20:n[/tex]
[tex]\bf 7= 27- 20:n[/tex]
[tex]\bf 7 + 20 : n = 27[/tex]
[tex]\bf 20 : n = 27 - 7[/tex]
[tex]\bf 20 : n = 20[/tex]
[tex]\bf 20 = 20n~~\bigg|:20\implies\boxed{\boxed{\bf n = 1}}[/tex]
dublul lui n este 2 × 1 = 2
1259 + 2 = 1261
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