Răspuns:
a) CH3-CH=C(CH3)- CH2-CH3
b) CH2= CH- CH(CH3) - CH2-CH3
c) CH3-CH=C(CH3)- CH2-CH3 + H2 → CH3-CH2-CH(CH3)- CH2-CH3
d) nr de moli de alchena = 170 g / 84g = 2,02 moli
m alcan = 2,02 · 172g =348,09g C6H14.
CH3-CH=C(CH3)- CH2-CH3 + Cl2 → CH3-CHCl-CCl(CH3)- CH2-CH3
n moli de alchena = 120 g/ 84g= 5,57 moli , rezulta acelasi nr de moli de compus diclorurat.
m = 5,57 · M diclorurat = 5,57 · 155g =863,35g 2,3 diclor,3metil-pentan.
arederea propenei:
C5H10 + 15/2 O2 → 5CO2 + 5H2O
500g = 0,5Kg propena
daca la arderea unui Kg de C5H10 se obtin 45,79 MJ
0,5 Kg rezulta .....?
Deci : Q = 45,79MJ / 2 = 22,89 KJ
