a) CuSO4 + 2NaOH --> Cu(OH)2 + Na2SO4
reactie de schimb (dublu schimb)
b)
M.CuSO4 = 64+32+4x16 = 160 g/mol
M.Cu(OH)2 = 60+2(16+1) = 98 g/mol
M.NaOH = 23+16+1 = 40 g/mol
M.Na2SO4 = 23x2+32+4x16 = 142 g/mol
480g m g n moli a moli
CuSO4 + 2NaOH --> Cu(OH)2 + Na2SO4
160 2x40 1 1
=> n = 480x1/160 = 3 moli CuSO4
n = nr.moli = m/M => m.Cu(OH)2 = nxM
= 3x98 = 294 g CuSO4
c)
=> m = 480x2x40/160 = 120 g NaOH format
d)
=> a = 480x1/160 = 3 moli sare Na2SO4
