Răspuns: Rezolvarea e mai jos
Explicație pas cu pas:
Salutare!
[tex]\bf a)~ 8x\cdot(2x-1)-6\cdot(2x-1)=[/tex]
[tex]\bf (2x-1)\cdot(8x-6)=[/tex]
[tex]\boxed{\bf 2\cdot(2x-1)\cdot(4x-3)}[/tex]
[tex]\it~~~[/tex]
[tex]\bf b)~ (3x+1)^{2}-5x\cdot(3x+1)-(3x+1)=[/tex]
[tex]\bf (3x+1)\cdot[(3x+1)-5x-1]=[/tex]
[tex]\bf (3x+1)\cdot(3x+1-5x-1)=[/tex]
[tex]\boxed{\bf -2x\cdot (3x+1)}[/tex]
[tex]\it~~[/tex]
[tex]\bf c)~ (x-1)\cdot(2x+3)-(x-1)\cdot(5x-1)=[/tex]
[tex]\bf (x-1)\cdot[(2x+3)-(5x-1)]=[/tex]
[tex]\bf (x-1)\cdot(2x+3-5x+1)=[/tex]
[tex]\boxed{\bf (x-1)\cdot(4-3x)}[/tex]
[tex]\it~~[/tex]
[tex]\bf d)~ 3x\sqrt{2}\cdot(2x+1)+5\sqrt{2}\cdot(2x+1)-7x^{2} \sqrt{2}\cdot(2x+1)=[/tex]
[tex]\boxed{\bf \sqrt{2}\cdot(2x+1)\cdot(3x+5-7x^{2} )}[/tex]
==pav38==
