Răspuns :
Fluor:
Z=9, A=19
nucleu: 9p+
n0 = A-Z = 19-9 = 10
structura electronica: 9e-
(1)K2e- (2)L7e-
al 9-lea element in S.P.
m = 19 g
=> 1 mol F2 = 19x2 = 38g si contine 2x6,022x10la23 atomi F
Clor:
Z=17, A=35
nucleu: 17p+
n0 = A-Z = 35-17 = 18
structura electronica: 17e-
(1)K2e- (2)L8e- (3)M7e-
al 17-lea element in S.P.
m = 35 g
=> 1 mol Cl2 = 2x35 = 70g si contine 2x6,022x10la23 atomi Cl
Brom
Z=35, A=80
nucleu: 35p+
n0 = A-Z = 80-35 = 45
structura electronica: 35e-
(1)K2e- (2)L8e- (3)M8e- (4)N17
al 35-lea element in S.P.
m = 80 g
=> 1 mol Br2 = 2x80 = 160g si contine 2x6,022x10la23 atomi Br
Iod:
Z=53, A=127
nucleu: 53p+
n0 = A-Z = 127-53 = 74
structura electronica: 53e-
(1)K2e- (2)L8e- (3)M8e- (4)N18 (5)O17e-
al 53-lea element in S.P.
m = 127 g
=> 1 mol l2 = 2x127 = 254g si contine 2x6,022x10la23 atomi l
Astatin:
Z=85, A=210
nucleu: 85p+
n0 = A-Z = 210-85 = 125
structura electronica: 85e-
(1)K2e- (2)L8e- (3)M8e- (4)N18 (5)O32e- (6)P17e-
al 85-lea element in S.P.
m = 210 g
=> 1 mol As2 = 2x210 = 420g si contine 2x6,022x10la23 atomi As