Răspuns :

Fluor:

Z=9, A=19

nucleu: 9p+

n0 = A-Z = 19-9 = 10

structura electronica: 9e-

(1)K2e- (2)L7e-

al 9-lea element in S.P.

m = 19 g

=> 1 mol F2 = 19x2 = 38g si contine 2x6,022x10la23 atomi F

Clor:

Z=17, A=35

nucleu: 17p+

n0 = A-Z = 35-17 = 18

structura electronica: 17e-

(1)K2e- (2)L8e- (3)M7e-

al 17-lea element in S.P.

m = 35 g

=> 1 mol Cl2 = 2x35 = 70g si contine 2x6,022x10la23 atomi Cl

Brom

Z=35, A=80

nucleu: 35p+

n0 = A-Z = 80-35 = 45

structura electronica: 35e-

(1)K2e- (2)L8e- (3)M8e- (4)N17

al 35-lea element in S.P.

m = 80 g

=> 1 mol Br2 = 2x80 = 160g si contine 2x6,022x10la23 atomi Br

Iod:

Z=53, A=127

nucleu: 53p+

n0 = A-Z = 127-53 = 74

structura electronica: 53e-

(1)K2e- (2)L8e- (3)M8e- (4)N18 (5)O17e-

al 53-lea element in S.P.

m = 127 g

=> 1 mol l2 = 2x127 = 254g si contine 2x6,022x10la23 atomi l

Astatin:

Z=85, A=210

nucleu: 85p+

n0 = A-Z = 210-85 = 125

structura electronica: 85e-

(1)K2e- (2)L8e- (3)M8e- (4)N18 (5)O32e- (6)P17e-

al 85-lea element in S.P.

m = 210 g

=> 1 mol As2 = 2x210 = 420g si contine 2x6,022x10la23 atomi As