Răspuns :
Bună!⚘
A:
[tex] \sqrt{3} ^{5} \times \sqrt{3} ^{3} = {3}^{4} [/tex]
C:
[tex] \sqrt{6} ^{3} \times \sqrt{6} ^{2} = \sqrt{6} ^{5} [/tex]
D:
[tex] \sqrt{6} ^{12} \times \sqrt{6} ^{ - 11} = {6}^{6} \times 6 ^ - { \frac { 11}{2} } = 6 ^{ \frac{1}{2} } = \sqrt{6} [/tex]
E:
[tex] \sqrt{11} ^{2} \times \sqrt{11} ^{5} = \sqrt{11} ^{7} [/tex]
I:
[tex] \sqrt{2} ^{3} \times \sqrt{7} ^{3} = ( \sqrt{2} \sqrt{7} ) ^{3} [/tex]
J:
[tex] \sqrt{6} ^{3} \times \sqrt{2} ^{3} = ( \sqrt{6} \sqrt{2} ) ^{3} [/tex]
☁️Succes!☁️
Explicație pas cu pas:
sper că te-am ajutat!(:
coroana?!