E.
a. se cere natura at. de C
1= cuaternar , 2 = tertiar , 3= primar
b.
Fm. = C8H16, miu = 8x12+16x1 = 112 g/mol
raport de masa:
C: H = 96: 16 /:16 = 6: 1
c.
daca la 112g C8H16 ..................... 96g C
x g C8H16 ........................ 72g C
= 84g C8H16
d.
Fm. omolog inferior = C7H14
Fm. omolog superior = C9H18
e.
CH3
CH3-C-CH2-C=CH2
CH3 CH3
2,5,5-trimetil-1-pentena
f.
CH2=CH-CH2-CH2-CH2-CH2-CH2-CH3
1-octena
