Răspuns:
d=distanta totala
in prima zi
35% x d i-au mai ramas 65 d/100
a doua zi
20% x65% xd=13% xd adica 13d/100km
i-au mai ramae de parcurs restul de(65d/100)-(13d/100)=(52d/100)km
a treia zi
52d/100=624km
52d=624x100
52d=62400
d=62400:52
d=1200km distanta totala
in prima zi parcurge(35x1200):100=42000:100=420km
dar ii mai raman de parcurs
1200-420=780kmm
a doua zi parcurgr(20x780):100=15600:100=156km
atreia zi parcurge
1200-(420+156)=1200-576=624km conform problemei