Răspuns :

Triunghiul1id

[tex]\frac{\overline{abc}+\overline{bca}+\overline{cab}}{a+b+c} =\frac{100a+10b+c+100b+10c+a+100c+10a+b}{a+b+c} =[/tex]

[tex]\frac{111a+111b+111c}{a+b+c} =\frac{111(a+b+c)}{a+b+c} ^{(a+b+c}=111[/tex]

Mausmini118id

[tex] \frac{abc + bca + cab}{ a + b + c} = \frac{100a + 10b + c + 100c + a + 100c + 10a + b}{111a + 111b + 111c} = \frac{111}{1} = 111[/tex]

Sper ca ti-am fost de folos. Succes!!!

ID Alte intrebari