Răspuns :
Răspuns:
a+a+1+a+2+a+3=50
4a+6=50
4a=50-6=>a=44:4=>a=11
11+1=12
11+2=13
11+3=14
nr consecutive sunt : 11,12,13,14
Răspuns:
A+(a+1)+(a+2)+(a+3)=50
4a+1+2+3=50
4a+6=50
4a=50-6
4a=44
a=44:4
a=11
Verificare: 11+(11+1)+(11+2)+(11+3)
11+12+13+14=50