Răspuns :

Răspuns:

Explicație pas cu pas:

a)

75 = 3*5^2

50 = 2*5^2

cmmdc = 5^2 = 25

b)

40 = 2^3*5

60 = 2^2*3*5

cmmdc = 2^2*5 = 20

c)

80 = 2^4*5

100 = 2^2*5^2

cmmdc = 2^2*5 = 20

d)

60 = 2^2*3*5

90 = 2*3^2*5

cmmdc = 2*3*5 = 30

e)

48 = 2^4*3

56 = 2^3*7

cmmdc = 2^3 = 8

f)

63 = 3^2*7

72 = 2^3*3^2

cmmdc = 3^2 = 9

g)

66 = 2*3*11

44 = 2^2*11

cmmdc = 2*11 = 22

h)

36 = 2^2*3^2

54 = 2*3^3

cmmdc = 2*3^2 = 18

Dianageorgiana794id

Răspuns:

- descompunerea numerelor intregi in factori primi

a) 75 = 3 × 5²

50 = 2 × 5²

- se inmultesc toti factorii primi comuni, la puterile cele mai mici

cmmdc (75; 50) = 5² = 25

_______

b) 40 = 2³ × 5

60 = 2² × 3 × 5

cmmdc (40; 60) = 2² × 5 = 20

_______

c) 80 = 2⁴ × 5

100 = 2² × 5²

cmmdc (80; 100) = 2² × 5 = 20

_________

d) 60 = 2² × 3 × 5

90 = 2 × 3² × 5

cmmdc (60; 90) = 2 × 3 × 5 = 30

____________

e) 48 = 2⁴ × 3

56 = 2³ × 7

cmmdc (48; 56) = 2³= 8

________

f) 63 = 3² × 7

72 = 2³ × 3²

cmmdc (63; 72) = 3² = 9

_________

g) 66 = 2 × 3 × 11

44 = 2² × 11

cmmdc (66; 44) = 2 × 11 = 22

________

h) 36 = 2² × 3²

54 = 2 × 3³

cmmdc (36; 54) = 2 × 3² = 18

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