22.4 L..................1 mol...............6,022x10^23 molecule...........64 g/mol
x L.........................y moli..............42,161x10^23 molecule............k g/mol
x = 22.4x42,161x10^23/6,022x10^23= 115,82 L SO2
y= 42,161x10^23/6,022x10^23 = 7 moli
k= 7xmasa molara = 7x64 = 448 g
