Răspuns:
1.
MH2=2×1=2g/mol
m=4×2=8gH2
MHCl=1+35,5=36,5g
2g...............2×36,5g
H2 + Cl2 → 2HCl
8g...............xg
x=8×2×36,5/2= calculeaza
2.
a)
MH2=2×1=2g/mol
MAlH3=27+3×1=30g/mol
3×2g....... 2×30g
2Al + 3H2 → 2AlH3
10g..........xg
x=10×2×30/3×2= calculeaza
b)
n=10/2=5moli H2
2moli.....3moli
2Al + 3H2 → 2AlH3
yg moli... 5moli
y=5×2/3= calculeaza
Explicație: