Răspuns:
20,4 g [tex]Al_2O_3[/tex]
Explicație:
[tex]2Al + \frac{3}{2} O_2 = Al_2O_3[/tex]
[tex]M_{{Al_2}{O_3}} = 2*M_{Al} + 3*M_O = 2*27 + 3*16 = 102 g/mol[/tex]
2*27 g Al...........102 g [tex]Al_2O_3[/tex]
10,8 g Al........... x g [tex]Al_2O_3[/tex]
=> x = (10,8*102)/(2*27) = 20,4 g [tex]Al_2O_3[/tex]