Calculati masa de clorura de sodiu care se formeaza prin reactia a 200g solutie de hidroxid de sodiu de concentratie 15 % cu acidul clorhidric.

NaOH + HCl -----------------> NaCl + H2O

Răspuns :

Răspuns:

ms=200g

C=15%

md=C×ms/100=15×200/100=30gNaOH

MNaOH =23+16+1=40g/mol

MNaCl =23+35,5=58,5g/mol

40g 58,5g

NaOH + HCl => NaCl + H2O

30g xg

x=30×58,5/40=43,875g NaCl