H2+Cl2 = 2 HCl
2g 71g 73g
1mol 1mol 2mol
a)
2mol HCl.....1mol Cl2.....1mol H2
6mol HC...........x..................y
x=6/2=3 moli de Cl2, care contine 3*A Cl2=3*35,5=106,5g
y=3 moli de H2, care contine 6 g
b)
73 g HCl............71 g Cl2........2 g H2
36500 g HCl.........x....................y
x=36500*71/73=35500 g de Cl2, 35500/71=500 moli Cl2
y=36500*2/73=1000 g de H2, 500 moli H2