Răspuns:
Explicație:
888g CaCl2
react. cu NaOH
g, moli Ca(OH)2
g,moli NaCl
888g xg yg
CaCl2 + 2NaOH= Ca(OH)2 + 2NaCl
111g 74g 2. 58,5g
x= 888 . 74 : 111 =592 g Ca(OH)2
n= 592g : 74 g/moli= 8 moli Ca(OH)2
y= 888 . 117 : 111=936 g NaCl
n= 936g : 58,5= 16 moli NaCl
1mol NaCl-------6,023.10²³atomi Na------11.6,023.10²³ e----10 . 6,023.10²³ioni
+ Na
16 moli--------------------------------------------------------------------------x Na
+
x= 16 . 10 . 6,023.10²³Na =
