Răspuns :

1. [tex]\frac{3\sqrt{5} - 3\sqrt{2} }{\sqrt{5} - \sqrt{2} }[/tex] = [tex]\frac{3(\sqrt{5}-\sqrt{2})}{\sqrt{5}-\sqrt{2}}[/tex] = [tex]\frac{3}{1}[/tex] = 3

2. [tex]\frac{\sqrt{3}*\sqrt{7}-\sqrt{3}*\sqrt{2}}{\sqrt{7}-\sqrt{2}}[/tex] = [tex]\frac{\sqrt{3}*(\sqrt{7}-\sqrt{2})}{\sqrt{7}-\sqrt{2}}[/tex] = [tex]\sqrt{3}[/tex]

3. [tex]\frac{\sqrt{2}*(\sqrt{13}-\sqrt{3}-\sqrt{7})}{\sqrt{13}-\sqrt{3}-\sqrt{7}}[/tex] = [tex]\sqrt{2}[/tex]

4. [tex]\frac{(\sqrt{5})^{3}}{\sqrt{5}}-\frac{\sqrt{4}*\sqrt{7} }{\sqrt{7} }+\frac{\sqrt{2}*\sqrt{16}}{\sqrt{2}}[/tex] = [tex]\sqrt{5}^{2}-\sqrt{4}+\sqrt{16}[/tex] = 25 - 2 + 4 = 27

5. [tex]\frac{\sqrt{16}*(\sqrt{5}+\sqrt{2}) }{\sqrt{5}+\sqrt{2}}-\frac{\sqrt{9}*(\sqrt{7}-\sqrt{3} ) }{\sqrt{7}-\sqrt{3}}[/tex] = [tex]\sqrt{16} - \sqrt{9}[/tex] = 4 - 3 = 1