Răspuns:
[tex]a\left(3\sqrt{2}-2\right)+b\left(5\sqrt{2}-3\right)=3\sqrt{2}-1=>\\a\left(3\sqrt{2}-2\right)=3\sqrt{2}-1-b\left(5\sqrt{2}-3\right)=>\\a=\frac{3\sqrt{2}-1-b\left(5\sqrt{2}-3\right)}{3\sqrt{2}-2}=>a=\frac{3\sqrt{2}-1-5b\sqrt{2}+3b}{3\sqrt{2}-2}=>\\a=\frac{\left(3\sqrt{2}-1-5b\sqrt{2}+3b\right)\left(3\sqrt{2}-2\right)}{14}=>\\a=\frac{18+6\sqrt{2}-3\sqrt{2}-2-30b-10b\sqrt{2}+9b\sqrt{2}+6b}{14}=>\\a=\frac{16+3\sqrt{2}-24b-b\sqrt{2}}{14}[/tex]
si b apartine R