Răspuns:
1. solutii/ mare/ diluata/ maxima
2.Trebuie ca masa dizolvantului sa fie mai mare decat masa dizolvatului
dizolvat/dizolvant: sare/ apa alcool/ apa soda de rufe /apa iod alcool apa/ alcool
3=c=mdx100/ms
md=25g
ms= md+m,apa= 400g
c=25x100/400=6,25%
4. c=7%
md=4,2g
ms= mdx100/c= 4,2x100/7g=60g
ms=md+m,alcool---> m,alcool=60-4,2g= 55,8g
5
ms1=50g c1=40%------> md1= 40x50/100g=20g
ms2=150g c2=50% md2= 50x150/100g=75g
c3= md3x100/ms3 md3=md1+md2= 95g
ms3=ms1+ms2= 200g
c 3=95x100/200=47,5%
Explicație:
