A) 12%
ms = 100 g => md = 100x12/100 = 12 g
B) 20%
=> md = 200x20/100 = 40 g
C) 24,5%
ms = 45x100/24,5 = 183,7
d.
ms.A = 100x100/12 = 833,33 g
ms.B = 100x100/20 = 500 g
ms.C = 100x100/24,5 = 408,2 g
avem ms = 200g c% = 12%
=> m.zahara = md = msxc%/100 = 200x12/100 = 24 g
ms = 400g => md = 400x12/100 = 48 g
ms = 200/2 = 100g , md = 100x12/100 = 12g
ms.final = 100+36 = 136g, md = 136x12/100 = 16,32 g
m.apa = m, c%.final = 12/2,5 = 4,8%
=> ms.final = ms+m
=> 4,8 = 24x100/(200+m) => m = 300 g apa adaugata
omogen
fizic ,
solubilitate
gradul de faramitare
diluarea
nesaturata
solutie
scaderea temperaturii
solvat
solutie
solida
12 g
182 g
ms = 182+12 = 200 g
c% = mdx100/ms = 12x100/200 = 6%
