Răspuns :

Triunghiul1id

[tex]2^{29}*5^{22}=x^2\\2^7*2^{22}*5^{22}=x^2\\2^7*(2*5)^{22}=x^2\\2^7*10^{22}=x^2\\x^2=2^7*10^{22}\\x^2=128*10^{22}\\x=\sqrt{128*10^{22}} \\x=8\sqrt{2} *10^{11}\\\\x_1=8*10^{11}\sqrt{2} \\x_2=-8*10^{11}\sqrt{2}[/tex]

Răspuns:

Explicație pas cu pas:

2^7 * 10^22 = x^2

2 * 2^6 * 10^22 = x^2

2^6 * 10^22 = (x^2)/2

(2^3 * 10^11)^2 = (x/V2)^2

x = V2((2^3 * 10^11)^2 )

V = radical

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