Răspuns:
1
Explicație pas cu pas:
[tex](\frac{2}{\sqrt{3} } +\frac{1}{3} +\frac{2}{\sqrt{7} } -\frac{1}{7} ):(\frac{6+\sqrt{3} }{3\sqrt{3} }+\frac{14-\sqrt{7} }{7\sqrt{7} } )=(\frac{6+\sqrt{3} }{3\sqrt{3} }+\frac{14-\sqrt{7} }{7\sqrt{7} } ):(\frac{6+\sqrt{3} }{3\sqrt{3} }+\frac{14-\sqrt{7} }{7\sqrt{7} } )=1[/tex]
