conform Teoremei Impartirii cu Rest=> D=I•C+R
d=i•c+r, unde i=11, deci r<11
cum c=r => c<11
Forma numerelor va fi : d=11•c+r, unde c=r , c,r<11
S= suma numerelor
S= (11•1+1) + (11•2+2) + (11•3+3) +...+ (11•10+10)
S= 11•1+ 11•2+ 11•3 +...+11•10 + 1+2+3...+10
S=11•(1+2+3+...+10) + (1+2+3+...+10)
S=(1+2+3+...+10)•(11+1)
S=(1+2+3+...+10)•12
[tex]s = \frac{10 \times 11}{2} \times 12[/tex]
S=10•11•12
S=1320
