a fost răspuns

efectuați calculele
[tex] \frac{8}{3 \sqrt{2} } - \frac{8}{2 \sqrt{2 } } + \frac{8}{6 \sqrt{2} } - \frac{8}{12 \sqrt{2} } [/tex]
[tex] \frac{24}{5 \sqrt{6} } - \frac{12}{ \sqrt{6} } + \frac{21}{10 \sqrt{6} } - \frac{28}{2 \sqrt{6} } [/tex]
[tex] \frac{7}{2 \sqrt{5} } + \frac{7}{3 \sqrt{5 -} } - \frac{7}{6 \sqrt{5} } + \frac{7}{5 \sqrt{5} } [/tex]
​

Răspuns :

Răspuns:

Explicație pas cu pas:

8/√2(1/3-1/2+1/6-1/12)=8/√2·(4-6+2-1)/12=-2/3√2=-√2/3

1/√6(24/5-12+21/10-14)=[(48+21)/10-26)]/√6=(69-260)/10√6=-191×√6/60

7/√5(1/2+1/3-1/6+1/5)=(15+10-5+6)·7/√5=26×7×√5/5=182√5/5