Răspuns :

Răspuns:

1.

[tex] \sqrt{16 } \div \sqrt{2} + \sqrt{18} \\ 2 \sqrt{2} + {3 \sqrt{2} } \\ = 5\sqrt{2 } \\ \\ \sqrt{3} \times \sqrt{15} - 2 \sqrt{75} \\ \sqrt{45} - 2 \sqrt{75} \\ 3 \sqrt{5} - 2 \times 5 \sqrt{3} \\ 3 \sqrt{5} - 10 \sqrt{3} \\ \\ \sqrt{120} \div \sqrt{10} - \sqrt{15} \div \sqrt{5 } \\ \sqrt{12} - \sqrt{3} \\ 2 \sqrt{3} - 1 \sqrt{3} \\ = 1 \sqrt{3} \\ \\ \sqrt{100} \div \sqrt{2} - \sqrt{40} \div \sqrt{5} \\ \sqrt{50} - \sqrt{8} \\ 5 \sqrt{2} - 2 \sqrt{2} \\ 3 \sqrt{2} [/tex]