Răspuns:
Explicație pas cu pas:
√(3 intregi si 1/5) = √[(3·5+1)/5] = √(16/5) = 4/√5 = 4√5/5
√0,8(3) = √[(83-8)/90] = √(75/90) = √(5/6) = √5·√6/6 = √30/6
√(10 intregi si 2/3) = √[(10·3+2)/3] = √(32/3) = √32·√3/3 = √96/3 =
= 4√6/3
√(81/24) = 9/(2√6) = 9√6/12 = 3√6/4
√(27/2) = 3√3/√2 = 3√3·√2/2 = 3√6/2
√√(400/121) = √(20/11) = √20·√11/11 = 2√5·√11/11 = 2√55/11
√(a²b/b³c) = √(a²/b²c) = a/b·√(1/c) = a√c/bc ; b ≠ 0 ; c > 0
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